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0=10x^2+30
We move all terms to the left:
0-(10x^2+30)=0
We add all the numbers together, and all the variables
-(10x^2+30)=0
We get rid of parentheses
-10x^2-30=0
a = -10; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·(-10)·(-30)
Δ = -1200
Delta is less than zero, so there is no solution for the equation
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